Determine the amount of rebar needed for the foundation walls shown in Figures 11.36 and 11.37. Allow for two inches of cover. Add 10 percent for lap and waste to the continuous bars.
What will be an ideal response?
From Problem 37, the length of the wall is 119.33?. The vertical bars are calculated as follows:
Number of spaces = 119.33? / 1? = 120 spaces
Add 1 to get the number of vertical bars – Use 121 bars
The vertical bars are 9?10? long (10? – 2?).
Total length of vertical bars (lf) = 121 bars × 9?10? per bar = 1,190 lf
Total weight of vertical bars (pounds) = 1,190 lf × 0.668 pounds per lf = 795 pounds
The horizontal bars are calculated as follows:
Number of spaces = 10? / 1? = 10 spaces
Add 1 to get the number of horizontal bars that are needed to meet the spacing requirements plus an additional top and bottom bar (10 + 1 + 1 + 1) – Use 13 bars
Total length of horizontal bars (lf) = 119.33? × 13 bars = 1,551 lf
Total weight of horizontal bars (pounds) = 1,551 lf × 0.668 pounds per lf = 1,036 pounds
Add for waste and lap.
Total weight of horizontal bars (pounds) = 1,036 pounds × 1.10 = 1,140 pounds
Total weight of rebar (pounds) = 795 pounds + 1,140 pounds = 1,935 pounds
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