Solve the problem.A projectile is fired from a height of 7.3 feet with an initial velocity of 122 ft/sec at an angle of 48° with the horizontal. The parametric equations for the path of the projectile are x = (122 cos 48°)t, and y = 7.3 + (122 sin 48°)t - 16t2,where x and y are in feet and t is in seconds. Determine the maximum height reached by the projectile. Round your answer to the nearest tenth of a foot.
A. 135.7 ft
B. 143 ft
C. 128.4 ft
D. 264.2 ft
Answer: A
Mathematics
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?
?
?
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D. 
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