If the Earth’s atmosphere is considered to extend from the surface to 20 km, the earth’s radius is 6,200 km, and the atmosphere is partitioned into cells spaced 0.5 km apart, how many floating?point calculations will be required to run one iteration of a global weather simulation, assuming that each cell requires 200 floating?point operations? If it requires 20 cycles (iterations) of simulation to calculate the weather over the next 24 hours, and a forecast is needed in 30 minutes, what must the FLOPS rating of the computing system be?
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The volume of a sphere is 4/3?r3. In this case we have two spheres, the Earth and the Earth + 20 km (i.e., including the atmosphere). The value of r is 6371 km. Consequently, the volume of the atmosphere is
If the sampling points are ½ km apart, there are 8 per km3 or 8.16 × 1010 for the entire atmosphere. Each point requires 20 iterations of 200 floating?point operations, so the total number of FLOPS per calculation is 3.264 × . If we wish to do this in 30 minutes (1,800 seconds) the number of operations per second is 3.264 ×
or 181 GFLOPS.
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