The subsequent problems deal with the circuit below:
When Vin is positive (e.g., 2V) and the diodes are assumed to be ideal (no drop), Vout (assuming the polarity shown) is equal to
A. Vin/2 (e.g., 1 V)
B. 0
C. Vin (e.g., 2 V)
D. ?Vin/2 (e.g., ?1 V)
E. ?Vin (e.g., ?2 V)
Answer: A
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