Solve the problem.The production level P of a factory during one time period is modeled by P(x, y) = Kx1/2y1/2 where K is a positive integer, x is the number of units of labor scheduled and y is the number of units of capital invested. If labor costs $500/unit, capital costs $800/unit and the owner has $1,900,000 available for one time period, what amount of labor and capital would maximize production?
A. 1900.0 units of labor and 1187.5 units of capital
B. 1583.3 units of labor and 1055.6 units of capital
C. 1187.5 units of labor and 1900.0 units of capital
D. 3800.0 units of labor and 2375.0 units of capital
Answer: A
Mathematics
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A. $373.13 B. $401.22 C. $402.08 D. $268.82
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Graph the function. Then use your graph to find the indicated limit.f(x) = sin x - 2, 
f(x)
A. -1 B. 3 C. -2 D. 1
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Factor completely.x6 - 2x5 - 63x4
A. x4(x - 9)(x - 7) B. x4(x - 9)(x + 7) C. x4(x + 9)(x + 7) D. x-9(x2 - 2x - 63)
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Solve.18 = 7x - 3
A. {5} B. {18} C. {14} D. {3}
Mathematics