Find the equation of the hyperbola satisfying the given conditions.Vertices at (0, ±3); foci at (0, ±6)
A. 
- 
= 1
B. 
- 
= 1
C. 
- 
= 1
D. 
- 
= 1
Answer: B
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Find the surface area of the surface S.S is the area cut from the plane z = 5y by the cylinder x2 + y2 = 36.
A. 36
B. 6
?
C. 12
?
D. 36
?
Solve the problem.The path of a projectile fired at an inclination ? to the horizontal with an initial speed vo is a parabola. The range R of the projectile, the horizontal distance that the projectile travels, is found by the formula src="https://sciemce.com/media/4/ppg__ttt0506190847__f1q224g4.jpg" alt="" style="vertical-align: -5.0px;" /> to the horizontal. Round your answer to two decimal places.
A. 912.23 ft
B. 1100.46 ft
C. 912.33 ft
D. 550.23 ft
where 
feet per second per second or 
meters per second per second. Find the range of a projectile fired with an initial velocity of 178 feet per second at an angle of
Round to the indicated place value.Round to the nearest one: 719.759
A. 719 B. 719.8 C. 720
Divide and simplify.
÷ 
A. - 
B. - 
C. 
D. 