The short data type requires two bytes of memory and stores an integer value in the range from -32,768 to +32,767. Since the int data type requires four bytes of memory, why is the range for the int data type much more than twice as much as that of the short data type? Be sure to show the math in your answer.
What will be an ideal response?
It is because of the number of bytes (bits) used in representing the numbers. Since the short data type uses 2 bytes (16 bits), these 2 bytes can represent 65536 different values. These range from -32,767 to + 32,768. In other words in binary, 2 to the 16th power is 65536.
The int data type on the other hand uses 4 bytes (32 bits). This number of bits can represent approximately 4 billion numbers (or - 2 billion to + 2 billion). More precisely, 2 to the 32nd power is 4,294,967,296; therefore the range would be from -2,147,483,648 to +2,147,483,647.
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