Solve the problem.A chemist needs 210 milliliters of a 41% solution but has only 5% and 68% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

A. 100 mL of 5%; 110 mL of 68%
B. 120 mL of 5%; 90 mL of 68%
C. 110 mL of 5%; 100 mL of 68%
D. 90 mL of 5%; 120 mL of 68%


Answer: D

Mathematics

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A.
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D.

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Mathematics