Rewrite Program 100 so that you normalize the first second of a sound, then slowly decrease the sound in steps of 1/5 for each following second. (How many samples are in a second? getSamplingRate is the number of samples per second for the given sound.)

Question

What will be an ideal response?

Answer 1

```
def increaseAndDecrease3(sound):
sampleRate = getSamplingRate(sound)
largest = -1
#Normalize
for sampleIndex in range(0,sampleRate):
largest = max(largest ,getSampleValueAt(sound, sampleIndex) )

multiplier = 32767.0 / largest

for sampleIndex in range(0,sampleRate):
louder = multiplier * getSampleValueAt(sound, sampleIndex)
setSampleValueAt(sound, sampleIndex,louder)

#Decrease by fifths
for sampleIndex in range(sampleRate, getLength(sound)):
amntToDecreaseBy = (int(sampleIndex)/int(sampleRate))*0.2
newVal = getSampleValueAt(sound, sampleIndex)*(1.0-amntToDecreaseBy)
setSampleValueAt(sound, sampleIndex,newVal)
```

Note: The first section is just a translation of Program 97. The second section “decreases” by making use of integer division, and then multiplying by (1amntToDeceaseBy) as multiplying by just amntToDecreaseBy would have the effect of increasing the values with time. Additionally, its worth noting that this function assumes a sound with a length greater than one, and that with sounds past six seconds in length
it will begin to show strange results as you’ll be multiplying by negative values.