A 3.0-m rod is pivoted about its left end. A force of 10 N is applied perpendicular to the rod at a distance of 1.2 m from the pivot causing a ccw torque, and a force of 5.2 N is applied at the end of the rod 3.0 m from the pivot. The 5.2-N force is at an angle of 30o to the rod and causes a cw torque. What is the net torque about the pivot? (Take ccw as positive.)
a. 18 N•m
c. 4.2 N•m
b. -18 N•m
d. -4.2 N•m
C
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