R-134a enters an insulated diffuser at a velocity of 200 m/s at a pressure and temperature of 800 kPa and 60°C, respectively. The R-134a exits at 1.60 MPa and 85°C. Determine the exit velocity.

Given: R-134a: P1 = 800 kPa; T1 = 60°C; V1 = 200 m/s; P2 = 1,600 kPa; T2 = 85°C
Insulated, so assume, Q?=0

What will be an ideal response?


For a diffuser, assume steady –state, steady-flow single-inlet, single-outlet flow, and assume that W?=?pe=0

These assumptions result in the first law being (State 1 is inlet, State 2 is outlet)



Finding R-134a properties: h1 = 294.98 kJ/kg; h2 = 309.73 kJ/kg

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