Solve the initial value problem.Differential Equation: 
= (-cos t)i + (4t3+ 8)jInitial Condition: r(0) = 4j
A. r(t) = (sin t)i + (12t2 + 4)j
B. r(t) = (-sin t)i + (t4+ 8t + 4)j
C. r(t) = (-sin t)i + (t4 + 4)j
D. r(t) = (-sin t)i + (t4)j
Answer: B
Mathematics
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