Consider the following ANOVA table.
?
Sourceof VariationSumof Squares
Degreesof Freedom
MeanSquare
F
Between Treatments2073.6
4
Between Blocks6000
5
1200
Error20
288
Total29
?
The null hypothesis for this ANOVA problem is
A. ?1 = ?2 = ?3 = ?4.
B. ?1 = ?2 = ?3 = ?4 = ?5.
C. ?1 = ?2 = ?3 = ?4 = ?5 = ?6.
D. ?1 = ?2 = ... = ?20.
Answer: B
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