An existing process involving polymers that re­duce friction loss in engines is described in Prob­lem 11.37. Assume it is possible to do an aug­mentation and upgrade to the existing process machinery that will provide a 2-year extension to its useful life. Call this Process M. The upgrade will cost $50,000 now, have an increased operat­ing cost of $9,000 per month, and no salvage value after the 2-year extension. Using the same criteria mentioned in Problem 11.37(b), that is, effective i = 1% per month and a 2-year study pe­riod, is it economically advantageous to upgrade (option M) or to purchase the equipment for Pro­cess K or L? Use a spreadsheet.ing polymers that re­duce friction loss in engines is described in Prob­lem 11.37. Assume it is possible to do an aug­mentation and

upgrade to the existing process machinery that will provide a 2-year extension to its useful life. Call this Process M. The upgrade will cost $50,000 now, have an increased operat­ing cost of $9,000 per month, and no salvage value after the 2-year extension. Using the same criteria mentioned in Problem 11.37(b), that is, effective i = 1% per month and a 2-year study pe­riod, is it economically advantageous to upgrade (option M) or to purchase the equipment for Pro­cess K or L?

In order to replace an old process for producing a polymer that reduces friction loss in engines, two current-technology machines have been identified. Process K will have a first cost of $160,000, an operating cost of $7000 per month, and a salvage value of $50,000 after 1 year and $40,000 after its maximum 2-year life.
Process L will have a first cost of $210,000, an operating cost of $5000 per month, and salvage values of $100,000 after 1 year, $70,000 after 2 years, $45,000 after 3 years, and $26,000 after its maximum 4-year life. You have been asked to de­termine which process is better using a study pe­riod of (a) 1 year, (b) 2 years, and (c) 3 years. The company’s MARR is 12% per year compounded monthly.


Process M (upgrade current machinery) is economically better (cell B11)

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