Solve the problem.The cross-sectional area of a cylinder is given by A = ?D2/4, where D is the cylinder diameter. Find the tolerance range of D such that 
< 0.01 as long as Dmin < D < Dmax.
A. Dmin = 3.567, Dmax = 3.570
B. Dmin = 3.558, Dmax = 3.570
C. Dmin = 3.567, Dmax = 3.578
D. Dmin = 3.558, Dmax = 3.578
Answer: A
Mathematics
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A. Converges B. Diverges
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A. 58 B. 45 C. 55 D. 50
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