Solve the problem.Use the Huntington-Hill method to apportion eleven seats among State X, State Y, and State Z. The populations of the states are state X, 4.0 million; State Y, 6.5 million; and State Z, 5.2 million. The current assignment of ten seats is State X has two seats, State Y has four seats, and State Z has four seats. Assign the eleventh and twelfth seat.
A. Eleventh seat: State X; Twelfth seat: State Y
B. Eleventh seat: State X; Twelfth seat: State Z
C. Eleventh seat: State Y; Twelfth seat: State Y
D. Eleventh seat: State Y; Twelfth seat: State Z
Answer: A
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+ 
)(
- 
)
A. 3 - 2
B. 3 - 2
C. 9
D. -3