Find Pk+1 from the given statement Pk.Pk: (k + 1)(k2 - k + 1) = k3 + 1
A. Pk+1: (k + 2)[(k + 1)2 - k + 2] = (k + 1)3 + 1
B. Pk+1: (k + 2)[(k + 1)2 - k + 2] = k3 + 2
C. Pk+1: (k + 2)[(k + 1)2 - k] = (k + 1)3 + 1
D. Pk+1: (k + 2)[(k + 1)2 - k] = k3 + 2
Answer: C
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