Solve for x in the proportion. If possible, reduce the known fraction first.
= 
A. x = 6
B. x = 2
C. x = 5
D. x = 4
Answer: B
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Sketch the graph and show all local extrema and inflection points.y = x
4
A. Local maximum: 
Local minimum: (6, 0)
Inflection points: 
, (6, 0)
B. Local maximum: 
Local minimum: (6, 0)
Inflection point: 
C. Local minimum: (6, 0)
No inflection points
D. Local maximum: 
Local minimum: (6, 0)
Inflection points: 
Solve the equation.
- 
= 0
A. {-7, 3} B. {-7} C. ? D. {3}
Solve the problem.In designing a flexible tubing system, the supports for the tubing must be perpendicular to the tubing. If a section of the tubing follows the curve 
along which lines must the supports be directed if they are located at 
and 
A. y = - 
x + 
, x = 0, y = 
x + 
B. y = - 
x + 
, x = 0, y = 
x + 
C. y = - 
x + 
, x = 0, y = 
x + 
D. y = - 
x + 
, x = 0, y = 
x + 
Find the absolute value.|0|
A. 2 B. 0 C. -1 D. 1