Solve the problem.The half-life of carbon-14 is 5730 years. This means that every 5730 years, the amount of carbon-14 is reduced by 50 percent. Assume that there are currently 3 milligrams of carbon-14 in a piece of petrified wood. Let f(t) represent the amount (in milligrams) of carbon-14 in the wood at t years from now.i) Find a formula for f.ii) How much carbon-14 will be in the piece of wood 1000 years from now?
What will be an ideal response?
| i) | f(t) = 3( )t/5730 or f(t) = 3(0.999879)t |
Mathematics
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