Solve the problem.Two cylindrical cans of beef stew sell for the same price. One can has a diameter of 8 inches and a height of 4 inches. The other has a diameter of 6 inches and a height of 7 inches. Which can contains more stew and is, therefore, a better buy?
A. The can with the diameter of 6 inches is the better buy.
B. The can with the diameter of 8 inches is the better buy.
C. They are both equally good buys.
Answer: B
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Reduce the fraction.
A. 
B. 
C. 
D. 
To answer the following question(s), refer to the Mandelbrot replacement process described by:? Start: Choose an arbitrary complex number s, called the seed of the Mandelbrot sequence. Set the seed s to be the initial term of the sequence 
? Procedure M: To find the next term in the sequence, square the preceding term and add the seed 
Suppose that we apply the Mandelbrot replacement process with s = 
. Then s2 =
A. 2 + 2
.
B. 6 + 
.
C. 4 + 
.
D. 6 + 5
.
E. none of these
Find the quadrant that contains the terminal side of angle ?.cos ? < 0 and sin ? > 0
A. I B. II C. III D. IV
Solve the problem.The cost function for the manufacture of graphing calculators is given by 
where x is the number of graphing calculators manufactured. Using the appropriate domain, sketch the graph of the average cost 
to manufacture x graphing calculators. Find the absolute minimum on the graph of 
. What do the coordinates of the absolute minimum tell us?
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A. The absolute minimum is at (31,622.78, 31.11). This tells us that the average cost of a graphing calculator is minimized at $31.11 per calculator when approximately 31,623 are produced.
B. The absolute minimum is at (34,825.23, 29.32). This tells us that the average cost of a graphing calculator is minimized at $29.32 per calculator when approximately 34,825.23 are produced.
C. The absolute minimum is at (31,622.78, 29.32). This tells us that the average cost of a graphing calculator is minimized at 
per calculator when approximately 31,623 are produced.
D. There is no absolute maximum.