Copper has a density of 555 lbm/ft3 and a specific heat of 0.0925 Btu/lbm-R. Consider that a block of copper undergoes a process which increases its pressure and temperature from 14.7 psi and 540 R to 295 psi and 720 K. Determine the change in specific internal energy and specific enthalpy for the copper in this process. No not neglect the pressure terms in the enthalpy calculation.
Given: Cu; p = 555 lbm/ft3; c = 0.0925 Btu/lbm-R; T1 = 540 R; P1 = 14.7 psi; T2 = 720K; P2 = 295 psi
What will be an ideal response?
v = 1/p = 0.00180 ft3/lbm
Assuming copper to be an incompressible substance with constant specific heats,
?u = c (T2 – T1) = 16.65 Btu/lbm
?h = c (T2 – T1) + v (P2 – P1)
= 16.65 Btu/lbm + (0.00180 ft3/lbm)(295 – 14.7)lbf/in2 (144 in2/ft2)(1 Btu/778.169 lbf-ft)
= 16.74 Btu/lbm
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