Solve the initial value problem.u''(x) = 12e2x - 8e-2x, u(0) = 10, u'(0) = 15
A. u = 3e2x + 2e-2x + 5x + 9
B. u = 3e2x - 2e-2x + 5x + 9
C. u = 3e2x - 2e-2x - 5x - 9
D. u = 3e2x + 2e-2x + 5x - 9
Answer: B
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