Find the slope of a line tangent to the given curve at the point P by finding the limit of the slopes of the secant lines PQ as Q approaches P.y = 6x2 - 3; P is (6, 213); let Q have x-values of 5.5, 5.9, 5.99, 5.999

A. Slopes: 66, 68.4, 68.94, 68.994
m = 69
B. Slopes: 9, 11.4, 11.94, 11.994
m = 12
C. Slopes: 69, 71.4, 71.94, 71.994
m = 72
D. Slopes: 33, 35.4, 35.94, 35.994
m = 36


Answer: C

Mathematics

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