Solve the initial value problem.u''(x) = 12e2x - 12e-2x, u(0) = 8, u'(0) = 14

A. u = 3e2x + 3e-2x + 2x + 8
B. u = 3e2x - 3e-2x + 2x + 8
C. u = 3e2x + 3e-2x + 2x - 8
D. u = 3e2x - 3e-2x - 2x - 8


Answer: B

Mathematics

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