Write a recursive method that will compute the number of odd digits in a number.
What will be an ideal response?
```
public static long countOdd(long number){
long result;
if(number == 0)
// base case
result = 0;
else {
long digit = number % 10;
if(digit < 0)
digit = -1 * digit;
if(digit % 2 == 1)
result = countOdd(number/10) + 1;
else
result = countOdd(number/10);
}
return result;
}
```
This code is in Methods.java.
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