Find the particular solution for the initial value problem. x 
= 4x2e2x; y(0) = 16
A. y = 4xe2x - 2e2x + 18
B. y = 2xe2x - e2x + 17
C. y = 2xe2x + 16
D. y = 4xe2x - e2x + 17
Answer: B
Mathematics
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