Find the general form of the equation of the the circle.Center at the point (-4, -3); containing the point (-3, 3)
A. x2 + y2 + 8x + 6y - 12 = 0
B. x2 + y2 - 6x + 6y - 12 = 0
C. x2 + y2 + 6x + 8y - 17 = 0
D. x2 + y2 + 6x - 6y - 17 = 0
Answer: A
Mathematics
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