For insulating a cylindrical vessel 14' in diameter with 3.5" thick block, how many lags per course will be required if the lag’s outer width is 4.5"?
a. 119
b. 121
c. 123
d. 125
c. 123
SOLUTION:
Convert vessel diameter to inches:
14 ft x 12"/ft = 168"
Calculate insulation diameter:
vessel diameter + 2 x insulation thickness = 168" + 3.5" + 3.5" = 175"
Calculate insulation circumference:
175" x 3.14 = 549.5"
Divide insulation by lag outer width:
549.5" ÷ 4.5" = 122.1 lags per course (round up to 123)
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