In a balanced Y-Y circuit shown below, the magnitude of the line voltage is VL = 535V (rms). The phase impedance is ZY = 75 + j42 ? per phase, the wire impedance is ZW = 15 + j11 ? per phase, the source impedance is ZS = 12 + j10 ? per phase. Find IA, VAN and VAB assuming ?Van = 0o.
Vp = VL/ 3 = 308.8824 V
Van = 308.8824?0o V
Vbn = 308.8824?-120o V
Vcn = 308.8824?120o V
Zt = ZS + ZW + ZY = 102 + j63
IA = Van/Zt = 2.5764?-31.7014o A
IB = Vbn/Zt = 2.5764?-151.7014o A
IC = Vcn/Zt = 2.5764?88.2986o A
VAN = ZY×IA = 221.4687?-2.4526o V
VBN = ZY×IB = 221.4687?-122.4526o V
VCN = ZY×IC = 221.4687?117.5474o V
VAB = VAN - VBN = 383.595?27.5474o V
f=60;w=2*pi*f
VL=535;Zy=75+42j;Zw=15+11j;Zs=12+10j;
Vp=VL/sqrt(3)
phi=0
Van=P2Rd(Vp,phi)
Vanp=R2P(Van)
Vbn=P2Rd(Vp,phi-120)
Vbnp=R2P(Vbn)
Vcn=P2Rd(Vp,phi-240)
Vcnp=R2P(Vcn)
Zt=Zw+Zy+Zs
IA=Van/Zt
IAp=R2P(IA)
IB=Vbn/Zt
IBp=R2P(IB)
IC=Vcn/Zt
ICp=R2P(IC)
VAN=Zy*IA
VANp=R2P(VAN)
VBN=Zy*IB
VBNp=R2P(VBN)
VCN=Zy*IC
VCNp=R2P(VCN)
VAB=VAN-VBN
VABp=R2P(VAB)
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