Which of the following is the version of func that is called?

Question

Suppose we have a class D derived from base class B,
```
class B
{
public:
// other members
void func();
// other members
};
void B::func() { /* body */}
class D: public B
{
public:
// other members
void func();
// other members
};
void D::func() { /* body */}
D dObj;
```

Make the following call using dObj as calling object:
dObj.func();

a)B::func()
b) D::func()
c) Neither
d) Both
e) This is illegal. The base class func() is inherited in the derived class. For this reason, it is illegal to have a function defined in a base class and in a derived class having the same signature.

Answer 1

b) D::func()