Find the exact value by using a half-angle identity.sin 
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Answer: C
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Solve.The distance an object travels after accelerating from an initial velocity is the product of velocity and the time added to one-half of the product of the acceleration and the square of the time. Write an expression for the height h of an object t seconds after being fired straight up into the air with an initial velocity of 288 m/sec. Then write the expression in factored form.[Note: The acceleration of an object fired vertically upwards is -9.8. m/s2]
A. 288t - 4.9t2 = t(288 - 4.9t) B. 288t - 4.9t2 = 4.9t(288 - t) C. 288t - 9.8t2 = t2(288 - 9.8t) D. 288t - 9.8t2 = t(288 - 9.8t)
Add or subtract as indicated.(5x8 + 9x6 - 10x3 + 9) - (10x8 - 10x4 + 9x3 - 3)
A. -5x8 + 9x6 + 10x4 - 19x3 + 12 B. 5x8 + 9x6 + 10x4 - 19x3 + 12 C. -5x8 + 9x6 - 10x4 - 19x3 + 12 D. 5x8 + 9x6 - 10x4 - 19x3 + 12
Find a system of inequalities with the given graph.
A. y ? -x + 6 y ? 2 y ? x B. y ? -x + 6 y ? 2 x ? 0 y ? 0 C. y ? -x + 6 y ? 2 y ? x D. y ? -x + 6 y ? 2 y ? x
Graph the system of inequalities.y ? -x2y ? x + 1y ? -5x ? -4
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