An electron with kinetic energy 2.80 eV encounters a potential barrier of height 4.70 eV. If the barrier width is 0.40 nm, what is the probability that the electron will tunnel through the barrier?
(1 eV = 1.60 × 10-19 J, mel = 9.11 × 10-31 kg, h = 1.055 × 10-34 J ? s,
h = 6.626 × 10-34 J ? s)
A) 3.5 × 10-3
B) 7.3 × 10-3
C) 1.4 × 10-2
D) 2.9 × 10-3
E) 3.5 × 10-2
Answer: A
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