Consider the best case. If an interrupt takes place and the first device polled is responsible, the time taken is 2 ?s (request) + 1.5 ?s (return) + 0.5 ?s (polling) + 5 ?s (interrupt handling). The total time is 9 ?s. This gives us a 50 ? 9 = 41 ?s margin on the response time of 50?s. Now, if the interrupting device is not first in the polling sequence, each poll takes an extra 0.5 ?s. With a 41 ?s margin we can perform 41/0.5 = 82 polls. Consequently, we can support 82 + 1 = 83 peripherals.
What will be an ideal response?
Consider the best case. If an interrupt takes place and the first device polled is responsible, the time taken is 2 ?s (request) + 1.5 ?s (return) + 0.5 ?s (polling) + 5 ?s (interrupt handling). The total time is 9 ?s. This gives us a 50 ? 9 = 41 ?s margin on the response time of 50?s. Now, if the interrupting device is not first in the polling sequence, each poll takes an extra 0.5 ?s. With a 41 ?s margin we can perform 41/0.5 = 82 polls. Consequently, we can support 82 + 1 = 83 peripherals.
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