Rewrite the given expression without exponents.t4
A. t ? t ? t ? t
B. t + 4
C. t + t + t + t
D. 
Answer: A
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The function s gives the displacement (in ft) of an object as a function of time (in seconds). Calculate values of the average velocity for the given values of t and find the instantaneous velocity at the indicated value of t by noting the limit of the average velocities.s = 5t - 4; when t = 4; use values of t of 3.5, 3.9, 3.99, 3.999
A. Average velocities: 19.5, 19.9, 19.99, 19.999
v = 20 ft/s
B. Average velocities: 20, 20, 20, 20
v = 20 ft/s
C. Average velocities: 5, 5, 5, 5
v = 5 ft/s
D. Average velocities: 4.5, 4.9, 4.99, 4.999
v = 5 ft/s
Solve the problem.The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 36 feet and the height of the arch over the center of the roadway is 10 feet. Two trucks plan to use this road. They are both 10 feet wide. Truck 1 has an overall height of 
and Truck 2 has an overall height of 
. Draw a rough sketch of the situation and determine which of the trucks can pass under the bridge.
A. Truck 1 can pass under the bridge, but Truck 2 cannot. B. Truck 2 can pass under the bridge, but Truck 1 cannot. C. Both Truck 1 and Truck 2 can pass under the bridge. D. Neither Truck 1 nor Truck 2 can pass under the bridge.
Use a percent proportion to answer the question.What is 36% of 1800 track events?
A. 64.8 track events B. 64,800 track events C. 648 track events D. 6480 track events
We are given a measurement of 
V. The tolerance is 
V.Find the upper limit, the lower limit, and the tolerance interval for the measurement.
A. 
B. 
C. 
D. 
E. 