Write an application that encodes English language phrases into Pig Latin. Pig Latin is a form of coded language often used for amusement. Many variations exist in the methods used to form Pig Latin phrases. For simplicity, use the following algorithm: To translate each English word into a Pig Latin word, place the first letter of the English word at the end of the word and add the letters

Question

“ay.” Thus, the word “jump” becomes “umpjay,” the word “the” becomes “hetay” and the word “computer” becomes “omputercay.” Blanks between words remain blanks. Assume the following: The English phrase consists of words separated by blanks, there are no punctuation marks and all words have two or more letters. Enable the user to input a sentence. Use a regex_token_iterator to divide the sentence into separate words. Function get- PigLatin should translate a single word into Pig Latin.

What will be an ideal response?

Answer 1

```
#include
#include
#include
using namespace std;

string getPigLatin( string );

int main()
{
string sentence, pigLatin;

// get the sentence from the user
cout << "Please enter a sentence: ";
getline( cin, sentence );

boost::sregex_token_iterator tokens( sentence.begin(), sentence.end(),
boost::regex( "\\s" ), -1 );
boost::sregex_token_iterator end;

while ( tokens != end )
{
pigLatin += getPigLatin( *tokens ) + " ";
++tokens;
} // end while

cout << pigLatin << endl;
} // end main

// translate a word into Pig Latin
string getPigLatin( string word )
{
// move the first letter at the end and add "ay"
word = word.substr( 1, word.size() - 1 ) + word[ 0 ] + "ay";
return word;
} // end function getPigLatin
```
Please enter a sentence: this is a sentence for translation
histay siay aay entencesay orfay ranslationtay