Solve the problem.In a 1-mile race, the winner crosses the finish line 10 feet ahead of the second-place runner and 27 feet ahead of the third-place runner. Assuming that each runner maintains a constant speed throughout the race, by how many feet does the second-place runner beat the third-place runner? (5280 feet in 1 mile.)
A. 17.03 ft
B. 7.01 ft
C. -10.05 ft
D. -17.09 ft
Answer: A
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Find the total surface area and the volume of the following right prism. (Round to the nearest tenth.)
A. T = 8177 in.2, V = 48,400 in.3 B. T = 5977 in.2, V = 48,400 in.3 C. T = 8177 in.2, V = 47,300 in.3 D. T = 5977 in.2, V = 47,300 in.3
Solve the equation.
= 2x
A. {3} B. {-3} C. ? D. {1}
Solve the problem.The surface area of a balloon is given by S(r) = 4?r2, where r is the radius of the balloon. If the radius is increasing with time t, as the balloon is being blown up, according to the formula 
find the surface area S as a function of the time t.
A. S(r(t)) = 
?t6
B. S(r(t)) = 
?t9
C. S(r(t)) = 
?t3
D. S(r(t)) = 
?t6
Find the product.3y3(3y - 1)(y + 4)
A. 42y4 - 12y3 B. 9y5 + 33y4 - 12y3 C. 9y5 - 12y3 D. 33y4 - 12y3