Solve the initial value problem.Differential Equation: 
= (t4 + 4t2)i + 4tjInitial Condition: r(0) = -5i + 2j
A. r(t) = 
i + (t2 + 2)j
B. r(t) = 
i + (2t2 + 2)j
C. r(t) = 
i + 2t2j
D. r(t) = 
i + (2t2 - 5)j
Answer: B
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