The distance in the x direction between two control points on a vertical aerial photograph is 4.5". If the distance between these same two points is 3.6" on another photograph having a scale of 1:24,000, determine the scale of the first vertical aerial photograph. If the focal length of the camera is 6"and the average elevation at these points is 100 ft, determine the flying height from which each photograph was taken.

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Let the actual distance between the points MN be x feet

M'N' = 3.6 in = 0.3 ft

(M'N') / (MN) = (ON') / (ON) = Scale 1:24,000

1 / 24000 = 0.3 / x

x = 7200 feet

Now solve for the scale of the second photo.

M'N = 4.5 in = 0.375 ft

Scale = 0.375 / 7200

Scale = 1:19,200

Now determine the height from which the first photo was

taken (H1).

1 / 19,200 = (6.0/12) / (H1 – 100)

H1 = 9,700 feet

Now determine the height from which the second photo was taken (H2).

1 / 24,000 = (6.0/12) / (H2 – 100)

H2 = 12,100 feet

Therefore, the scale of the first photograph is 1:19,200, the elevation it was taken

from is 9,700 feet, and the second photograph was taken at an elevation of 12,100

feet.

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