Solve the problem.The nationwide attendance per day for a certain motion picture can be approximated using the equation A(t) = 12t2e-t, where A is the attendance per day in thousands of persons and t is the number of months since the release of the film. Find and interpret the rate of change of the daily attendance after 4 months.
A. -3.517 thousand persons/day ? month; the change in daily attendance is decreasing.
B. 1.758 thousand persons/day ? month; the change in the daily attendance is increasing.
C. 3.517 thousand persons/day ? month; the daily attendance is increasing.
D. -1.758 thousand persons/day ? month; the daily attendance is decreasing.
Answer: D
You might also like to view...
Approximate the given square root to the nearest tenth using the guess-and-check method.
A. 11.5 B. 11.3 C. 11.2 D. 11.4
Complete the table. ObjectYards(yd)Centimeters(cm)Inches(in.)Meters(m)Millimeters(mm)Height of a plant ?35?
A.
Object | Yards (yd) | Centimeters (cm) | Inches (in.) | Meters (m) | Millimeters (mm) |
Height of a plant | 0.0383? | 3.5? | 1.3780? | 0.035? | 35? |
B.
Object | Yards (yd) | Centimeters (cm) | Inches (in.) | Meters (m) | Millimeters (mm) |
Height of a plant | 0.3199? | 3.5? | 1.3780? | 0.035? | 35? |
C.
Object | Yards (yd) | Centimeters (cm) | Inches (in.) | Meters (m) | Millimeters (mm) |
Height of a plant | 0.0383? | 0.35? | 1.3780? | 0.0035? | 35? |
D.
Object | Yards (yd) | Centimeters (cm) | Inches (in.) | Meters (m) | Millimeters (mm) |
Height of a plant | 0.3199? | 0.35? | 8.89? | 0.035? | 35? |
Solve the problem.A certain noise measures 109 decibels in loudness. If the intensity is multiplied by 100, how many decibels will the new noise measure?
A. 111 dB B. 129 dB C. 218 dB D. 10,900 dB
Solve the problem. Give the answer to the nearest thousandth if necessary.A painter leans a ladder against one wall of a house (as shown below). The ladder is 26 ft long. The base of the ladder is 20 ft from the house. How high is the wall?
A. 16.613 ft B. 23 ft C. 8.307 ft D. 138 ft