Write the standard form of the equation of the parabola with focus 
and its vertex at 
.
A. 
B. 
C. 
D. 
E. 
Answer: E
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Rotate the axes so that the new equation contains no xy-term. Discuss the new equation.17x2 - 12xy + 8y2 - 68x + 24y -12 = 0
A. ? = 63.4°
x'2 = -16y'
parabola
vertex at (0, 0)
focus at (0, -4)
B. ? = 63.4°
+ 
= 1
ellipse
center at (
, - 
)
major axis is x'-axis
vertices at (4 + 
, - 
) and (-4 + 
, - 
)
C. ? = 26.6°
+ 
= 1
ellipse
center at (0, 0)
major axis is y'-axis
vertices at (0, ±4)
D. ? = 63.4°
- 
= 1
hyperbola
center at (0, 0)
transverse axis is the x'-axis
vertices at (±4, 0)
The circumference of a sphere was measured to be 86 cm with a possible error of 0.8 cm. Use differentials to estimate the maximum error in the calculated volume.
What will be an ideal response?
Give a formula for a piecewise-defined function f for the graph shown.
A.
f(x) = 
B.
f(x) = 
C.
f(x) = 
D.
f(x) = 
For the given functions f and g, find the requested function and state its domain.f(x) = 2x3 + 3; g(x) = 6x2 - 1Find f ? g.
A. (f ? g)(x) = 12x5 - 2x3 + 18x2 - 3; (-?, 0) ? (0, ?) B. (f ? g)(x) = 2x3 + 6x2 - 3; (-?, ?) C. (f ? g)(x) = 12x6 - 2x3 + 18x2 - 3; (-?, ?) D. (f ? g)(x) = 12x5 - 2x3 + 18x2 - 3; (-?, ?)