Solve the problem.A projectile is fired from a height of 7.3 feet with an initial velocity of 148 ft/sec at an angle of 56° with the horizontal. The parametric equations for the path of the projectile are x = (148 cos 56°)t, and y = 7.3 + (148 sin 56°)t - 16t2,where x and y are in feet and t is in seconds. Find the height of the projectile after 4 seconds. Round your answer to the nearest tenth of a foot.
A. 242.1 ft
B. 434.1 ft
C. 234.8 ft
D. 331 ft
Answer: A
Mathematics
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