Which substance is not capable of diffusing across the endothelial cells of a capillary?
a. Carbon dioxide
b. None are capable of diffusing across the endothelial cells
c. All are capable of diffusing across the endothelial cells.
d. Small lipid soluble molecules
e. Oxygen
c
You might also like to view...
If cells of an individual contain the same set of genes, how do these cells become different from each other during development?
A) Different cell type-specific regulatory elements in DNA are created during development. B) Different cell type-specific regulatory elements in DNA are selectively lost during development. C) Differences in extracellular signals received by each cell lead to differences in the types of regulatory proteins present in each cell. D) Differences develop in promoter sequences that lead to different signals being produced by each type of cell.
Kisspeptin is a protein (coded for by the KISS-1 gene) that in humans has an important role in initiating secretion of gonadotropin-releasing hormone (GnRH),
a hormone that stimulates the anterior pituitary gland to release other hormones related to reproduction. Endocrinologists are finding that the protein kisspeptin and its receptor are central to sexual maturation at puberty. The receptor for kisspeptin is coded for by the gene GPR54. Given the information above, the product of GPR54 is: A. a steroid. B. an intracellular protein. C. an extracellular protein. D. an amine. E. a transmembrane protein.
Which statement is false regarding schizophrenia?
a. The genes responsible along with the environmental conditions have now been identified. b. The disorder is characterized by delusion, hallucinations, and abnormal social behavior. c. Exceptional creativity is often associated with it. d. Affected individuals show altered gene expression in certain brain regions. e. Family trees point to a genetic basis.
Bacteriophage replication differs from animal virus replication because only bacteriophage replication involves
A) adsorption to specific receptors. B) assembly of viral components. C) replication of viral nucleic acid. D) injection of naked nucleic acid into the host cell. E) lysis of the host cell.