Perform the indicated operation. Simplify if possible.
- 4
A. 
B. 7x - 4
C. 7 - 4x
D. 
Answer: D
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Provide an appropriate response.The area under the standard normal curve between 1 and 2 is equal to 0.1359. Scores on a particular aptitude test are normally distributed with a mean of 100 and a standard deviation of 10. Which of the following are equal to 13.59%?a. The percentage of scores between 120 and 130b. The percentage of scores between 110 and 120c. The percentage of scores between 80 and 90d. The percentage of scores between 90 and 120
A. a B. d C. b D. b, c E. a, b
Solve using the percentage formula.What number is 145% of 4,760?
A. 69,020 B. 690 C. 6,902 D. 690,200
Use a calculator to find the approximate value of the composition. Round answers to four decimal places. The expression may be undefined.sin 
A. 2.9 B. 0 C. -2.9 D. Undefined
Solve the system using determinants.2x + y + 
z = 13
x + 2z = -8x -2y = -4
A. (8, 7, -9) B. (8, 6, -6) C. (6, 5, -6) D. (12, 6, -4)