Referring to the figure below, let E1 = 10 V, E2 = 20 V, R1 = 4.7 Kê, R2 = 1 Kê, and R3 = 3.3 Kê. Solve for I1 and I2.
a. I1 = -3.15 mA I2 = 9.18 mA
b. I1 = -3.35 mA I2 = 7.69 mA
c. I1 = 4.02 mA I2 = -7.69 mA
d. I1 = 2.67 mA I2 = 5.27 mA
e. I1 = 3.15 mA I2 = 7.69 mA
d. I1 = 2.67 mA I2 = 5.27 mA
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÷ 
A. 
B. 
C. 
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