Solve the problem.A projectile is fired from a height of 9.3 feet with an initial velocity of 184 ft/sec at an angle of 40° with the horizontal. The parametric equations for the path of the projectile are x = (184 cos 40°)t, and y = 9.3 + (184 sin 40°)t - 16t2,where x and y are in feet and t is in seconds. Determine the rectangular equation describing the path of the projectile.
A. y = 9.3 + x tan 40° - 
x2
B. y = 9.3 + 184x tan 40° - 
x2
C. y = 9.3 + 184x tan 40° - 
x2
D. y = 9.3 + x tan 40° - 
x2
Answer: D
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= 
B. 
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+ 
C. 
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A. 
B. 
C. 
D. 