Solve the problem.The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of
is needed to keep an
car traveling at 20 mph from skidding on a curve of radius
what force would be required to keep the same car from skidding on a curve of radius
style="vertical-align: -4.0px;" /> at Round your answer to the nearest pound of force?
A. 20,769 lb
B. 20,637 lb
C. 20,801 lb
D. 21,339 lb
Answer: A
Mathematics
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Find the length and direction (when defined) of u × v.u = 4i + 2j + 8k, v = -i - 2j - 2k
A. 6;
i +
k
B. 180; i +
j +
k
C. 6;
i -
k
D. 180; i +
k
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Vectors A and B are at right angles. Find the magnitude and direction (from vector A) of the resultant.A = 382B = 204
A. R = 433.1, ? = 28.1° B. R = 433.1, ? = 61.9° C. R = 24.2, ? = 61.9° D. R = 24.2, ? = 28.1°
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Combine like terms.-9y - 2x - 7x
A. -9y - 9x B. -9y + 5x C. -18xy D. -9y - 5x
Mathematics
Rewrite as a single logarithm.2 log2(2x + 5) + 6 log2(6x + 1)
A. 12 log2(2x + 5)(6x + 1)
B. log2((2x + 5)2 + (6x + 1)6)
C. log2(2x + 5)2(6x + 1)6
D. log2
Mathematics