Solve the problem.A population of algae consists of 4000 algae at time t = 0. Conditions will support at most 600,000 algae. Assume that the rate of growth of algae is proportional both to the number present (in thousands) and to the difference between 600,000 and the number present (in thousands). Write a differential equation using 0.03 for the constant of proportionality.
A. dy/dt = 0.03y(600 - y)
B. dy/dt = 4000y(600 - 0.03y)
C. dy/dt = 0.03(600 - y)
D. dy/dt = 0.03y(y - 600)
Answer: A
Mathematics
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