Rewrite the equation in standard form. Find the center and radius of the circle.x2 + y2 + 6x - 4y - 48 = 0
A. (x + 6)2 + (y - 4)2 = 4
center (-6, 4), r = 2
B. (x - 6)2 + (y + 4)2 = 4
center (-6, 4), r = 2
C. (x + 6)2 + (y - 4)2 = 4
center (6, -4), r = 2
D. (x - 6)2 + (y + 4)2 = 4
center (6, -4), r = 2
Answer: A
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A.
B.
C.
D.
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A.
B.
C.
D.