Identify equilibrium values and determine which are stable and which are unstable.y' = (y - 2)(y - 4)(y - 5)

A. y = 5 is a stable equilibrium value and y = 4 and y = 2 are unstable equilibria.
B. y = 4 is a stable equilibrium value and y = 2 and y = 5 are unstable equilibria.
C. y = 5, y = 2 and y = 5 are unstable equilibria.
D. y = 2 is a stable equilibrium value and y = 4 and y = 5 are unstable equilibria.


Answer: B

Mathematics

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