Solve the problem.A projectile is fired from a height of 8.9 feet with an initial velocity of 156 ft/sec at an angle of 41° with the horizontal. The parametric equations for the path of the projectile are x = (156 cos 41°)t, and y = 8.9 + (156 sin 41°)t - 16t2,where x and y are in feet and t is in seconds. Find the height of the projectile after 3 seconds. Round your answer to the nearest tenth of a foot.
A. 267.9 ft
B. 353.2 ft
C. 171.9 ft
D. 163 ft
Answer: C
Mathematics
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